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3 Enter a name for your movie (and a location if you like) 4 Click OK to begin the rendering process As this shows, ArcSoft ShowBiz

let Fc be a canonical cover for F; i := 0; for each functional dependency in Fc do if none of the schemas Rj , j = 1, 2, , i contains then begin i := i + 1; Ri := ; end if none of the schemas Rj , j = 1, 2, , i contains a candidate key for R then begin i := i + 1; Ri := any candidate key for R; end return (R1 , R2 , , Ri ) Figure 714 Dependency-preserving, lossless-join decomposition into 3NF

cal cover for F Note that the algorithm considers the set of schemas Rj , j = 1, 2, , i; initially i = 0, and in this case the set is empty To illustrate the algorithm of Figure 714, consider the following extension to the Banker-schema in Section 76: Banker-info-schema = (branch-name, customer-name, banker-name, of ce-number) The main difference here is that we include the banker s of ce number as part of the information The functional dependencies for this relation schema are banker-name branch-name of ce-number customer-name branch-name banker-name The for loop in the algorithm causes us to include the following schemas in our decomposition: Banker-of ce-schema = (banker-name, branch-name, of ce-number) Banker-schema = (customer-name, branch-name, banker-name) Since Banker-schema contains a candidate key for Banker-info-schema, we are nished with the decomposition process The algorithm ensures the preservation of dependencies by explicitly building a schema for each dependency in a canonical cover It ensures that the decomposition is a lossless-join decomposition by guaranteeing that at least one schema contains a candidate key for the schema being decomposed Exercise 719 provides some insight into the proof that this suf ces to guarantee a lossless join This algorithm is also called the 3NF synthesis algorithm, since it takes a set of dependencies and adds one schema at a time, instead of decomposing the initial schema repeatedly The result is not uniquely de ned, since a set of functional dependencies

We conclude the chapter with two de nitions that will prove useful later when examining the stability of circuits These are the poles and zeros of a function Our concern in circuit analysis will be a function in the s domain Let s say it s a rational function that can be written in the form F(s) = A(s) B(s)

The McGraw Hill Companies, 2001

will report on its progress as it is rendering the movie (see the progress percentage indicator in the upper-right corner of the viewer window)

Find the names of all branches with customers who have an account in the bank and who live in Harrison branch-name ( customer -city = Harrison (customer

depositor ))

The result relation for this query appears in Figure 322 Notice that we wrote customer 1 account 1 depositor without inserting parentheses to specify the order in which the natural-join operations on the three relations should be executed In the preceding case, there are two possibilities: (customer 1 account) 1 depositor customer 1 (account 1 depositor )

The zeros of the function, as you might guess, are simply calculated by setting F(s) = 0

We did not specify which expression we intended, because the two are equivalent That is, the natural join is associative Find all customers who have both a loan and an account at the bank customer -name (borrower

When ArcSoft ShowBiz finishes producing your movie, you will be returned to Sonic MyDVD The edited version of your movie will now appear on the menu along with the original, unedited versions of the clips You ll probably want to delete the unedited clips and keep just the edited version on the menu

depositor )